Base | Representation |
---|---|
bin | 10110110000111100111101… |
… | …110101010001001011010111 |
3 | 111010111110212000211002010121 |
4 | 112300330331311101023113 |
5 | 101110340322110324343 |
6 | 552534543413332411 |
7 | 30042335132232301 |
oct | 2660747565211327 |
9 | 433443760732117 |
10 | 100121020011223 |
11 | 299a10a4712882 |
12 | b29015b037107 |
13 | 43b34aa755a43 |
14 | 1aa1c517d4971 |
15 | b8959e0aaaed |
hex | 5b0f3dd512d7 |
100121020011223 has 2 divisors, whose sum is σ = 100121020011224. Its totient is φ = 100121020011222.
The previous prime is 100121020011217. The next prime is 100121020011283. The reversal of 100121020011223 is 322110020121001.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-100121020011223 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 100121020011197 and 100121020011206.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (100121020011203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50060510005611 + 50060510005612.
It is an arithmetic number, because the mean of its divisors is an integer number (50060510005612).
Almost surely, 2100121020011223 is an apocalyptic number.
100121020011223 is a deficient number, since it is larger than the sum of its proper divisors (1).
100121020011223 is an equidigital number, since it uses as much as digits as its factorization.
100121020011223 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 100121020011223 its reverse (322110020121001), we get a palindrome (422231040132224).
The spelling of 100121020011223 in words is "one hundred trillion, one hundred twenty-one billion, twenty million, eleven thousand, two hundred twenty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •