Search a number
-
+
10012103311211 is a prime number
BaseRepresentation
bin1001000110110001111111…
…0111000111111101101011
31022110010222200202011111222
42101230133313013331223
52303014241421424321
633143255145012255
72052231152654021
oct221543767077553
938403880664458
1010012103311211
113210122338961
1211584b518408b
135781a2822a31
14268834760711
151256877be3ab
hex91b1fdc7f6b

10012103311211 has 2 divisors, whose sum is σ = 10012103311212. Its totient is φ = 10012103311210.

The previous prime is 10012103311157. The next prime is 10012103311213. The reversal of 10012103311211 is 11211330121001.

It is a strong prime.

It is an emirp because it is prime and its reverse (11211330121001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10012103311211 - 222 = 10012099116907 is a prime.

Together with 10012103311213, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 10012103311211.

It is not a weakly prime, because it can be changed into another prime (10012103311213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5006051655605 + 5006051655606.

It is an arithmetic number, because the mean of its divisors is an integer number (5006051655606).

Almost surely, 210012103311211 is an apocalyptic number.

10012103311211 is a deficient number, since it is larger than the sum of its proper divisors (1).

10012103311211 is an equidigital number, since it uses as much as digits as its factorization.

10012103311211 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36, while the sum is 17.

Adding to 10012103311211 its reverse (11211330121001), we get a palindrome (21223433432212).

The spelling of 10012103311211 in words is "ten trillion, twelve billion, one hundred three million, three hundred eleven thousand, two hundred eleven".