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10012110110953 is a prime number
BaseRepresentation
bin1001000110110010000001…
…0001000100000011101001
31022110011000011112122000021
42101230200101010003221
52303014300142022303
633143255550440441
72052231264524236
oct221544021040351
938404004478007
1010012110110953
113210126162685
1211584b7503121
135781a4063a52
1426883561078d
151256881b3ebd
hex91b204440e9

10012110110953 has 2 divisors, whose sum is σ = 10012110110954. Its totient is φ = 10012110110952.

The previous prime is 10012110110941. The next prime is 10012110111071. The reversal of 10012110110953 is 35901101121001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6945923502144 + 3066186608809 = 2635512^2 + 1751053^2 .

It is a cyclic number.

It is not a de Polignac number, because 10012110110953 - 229 = 10011573240041 is a prime.

It is a super-3 number, since 3×100121101109533 (a number of 40 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (10012113110953) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5006055055476 + 5006055055477.

It is an arithmetic number, because the mean of its divisors is an integer number (5006055055477).

Almost surely, 210012110110953 is an apocalyptic number.

It is an amenable number.

10012110110953 is a deficient number, since it is larger than the sum of its proper divisors (1).

10012110110953 is an equidigital number, since it uses as much as digits as its factorization.

10012110110953 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 270, while the sum is 25.

Adding to 10012110110953 its reverse (35901101121001), we get a palindrome (45913211231954).

The spelling of 10012110110953 in words is "ten trillion, twelve billion, one hundred ten million, one hundred ten thousand, nine hundred fifty-three".