Base | Representation |
---|---|
bin | 10110110000111101000010… |
… | …101110000100101011100111 |
3 | 111010111111001202010002211111 |
4 | 112300331002232010223213 |
5 | 101110341004103323421 |
6 | 552534555503045451 |
7 | 30042340146225106 |
oct | 2660750256045347 |
9 | 433444052102744 |
10 | 100121102011111 |
11 | 299a1136a2a585 |
12 | b2901825a0887 |
13 | 43b34c173649c |
14 | 1aa1c5c65c03d |
15 | b895a63a6ee1 |
hex | 5b0f42b84ae7 |
100121102011111 has 2 divisors, whose sum is σ = 100121102011112. Its totient is φ = 100121102011110.
The previous prime is 100121102011103. The next prime is 100121102011163. The reversal of 100121102011111 is 111110201121001.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 100121102011111 - 23 = 100121102011103 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 100121102011091 and 100121102011100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (100121102011171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50060551005555 + 50060551005556.
It is an arithmetic number, because the mean of its divisors is an integer number (50060551005556).
Almost surely, 2100121102011111 is an apocalyptic number.
100121102011111 is a deficient number, since it is larger than the sum of its proper divisors (1).
100121102011111 is an equidigital number, since it uses as much as digits as its factorization.
100121102011111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4, while the sum is 13.
Adding to 100121102011111 its reverse (111110201121001), we get a palindrome (211231303132112).
The spelling of 100121102011111 in words is "one hundred trillion, one hundred twenty-one billion, one hundred two million, eleven thousand, one hundred eleven".
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