100121200212113 has 2 divisors, whose sum is σ = 100121200212114. Its totient is φ = 100121200212112.

The previous prime is 100121200212071. The next prime is 100121200212179. The reversal of 100121200212113 is 311212002121001.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 95742761141329 + 4378439070784 = 9784823^2 + 2092472^2 .

It is an emirp because it is prime and its reverse (311212002121001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 100121200212113 - 2²⁰ = 100121199163537 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 100121200212091 and 100121200212100.

It is not a weakly prime, because it can be changed into another prime (100121200212193) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50060600106056 + 50060600106057.

It is an arithmetic number, because the mean of its divisors is an integer number (50060600106057).

Almost surely, 2^{100121200212113} is an apocalyptic number.

It is an amenable number.

100121200212113 is a deficient number, since it is larger than the sum of its proper divisors (1).

100121200212113 is an equidigital number, since it uses as much as digits as its factorization.

100121200212113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 100121200212113 its reverse (311212002121001), we get a palindrome (411333202333114).

The spelling of 100121200212113 in words is "one hundred trillion, one hundred twenty-one billion, two hundred million, two hundred twelve thousand, one hundred thirteen".