Base | Representation |
---|---|
bin | 10110110000111101001001… |
… | …110001000000110000111011 |
3 | 111010111111100222112211200222 |
4 | 112300331021301000300323 |
5 | 101110341224334101021 |
6 | 552535015324450255 |
7 | 30042343113055232 |
oct | 2660751161006073 |
9 | 433444328484628 |
10 | 100121220222011 |
11 | 299a119772a13a |
12 | b2901b60a998b |
13 | 43b3510084c71 |
14 | 1aa1c7022db19 |
15 | b895b19576ab |
hex | 5b0f49c40c3b |
100121220222011 has 2 divisors, whose sum is σ = 100121220222012. Its totient is φ = 100121220222010.
The previous prime is 100121220221987. The next prime is 100121220222029. The reversal of 100121220222011 is 110222022121001.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-100121220222011 is a prime.
It is a super-2 number, since 2×1001212202220112 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (100121220222061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50060610111005 + 50060610111006.
It is an arithmetic number, because the mean of its divisors is an integer number (50060610111006).
Almost surely, 2100121220222011 is an apocalyptic number.
100121220222011 is a deficient number, since it is larger than the sum of its proper divisors (1).
100121220222011 is an equidigital number, since it uses as much as digits as its factorization.
100121220222011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64, while the sum is 17.
Adding to 100121220222011 its reverse (110222022121001), we get a palindrome (210343242343012).
The spelling of 100121220222011 in words is "one hundred trillion, one hundred twenty-one billion, two hundred twenty million, two hundred twenty-two thousand, eleven".
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