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100121323147 is a prime number
BaseRepresentation
bin101110100111110110…
…0100010011010001011
3100120102121221012022121
41131033230202122023
53120022024320042
6113554535232111
710143046130206
oct1351754423213
9316377835277
10100121323147
1139508970a6a
12174a2518637
1395979aa9a1
144bbb20293d
15290ec02367
hex174fb2268b

100121323147 has 2 divisors, whose sum is σ = 100121323148. Its totient is φ = 100121323146.

The previous prime is 100121323073. The next prime is 100121323223. The reversal of 100121323147 is 741323121001.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-100121323147 is a prime.

It is not a weakly prime, because it can be changed into another prime (100121326147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50060661573 + 50060661574.

It is an arithmetic number, because the mean of its divisors is an integer number (50060661574).

Almost surely, 2100121323147 is an apocalyptic number.

100121323147 is a deficient number, since it is larger than the sum of its proper divisors (1).

100121323147 is an equidigital number, since it uses as much as digits as its factorization.

100121323147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1008, while the sum is 25.

Adding to 100121323147 its reverse (741323121001), we get a palindrome (841444444148).

The spelling of 100121323147 in words is "one hundred billion, one hundred twenty-one million, three hundred twenty-three thousand, one hundred forty-seven".