Base | Representation |
---|---|
bin | 1001000110110010000110… |
… | …1000111000111100101001 |
3 | 1022110011001202212022212012 |
4 | 2101230201220320330221 |
5 | 2303014322040242441 |
6 | 33143302132125305 |
7 | 2052231664314206 |
oct | 221544150707451 |
9 | 38404052768765 |
10 | 10012133134121 |
11 | 3210138158298 |
12 | 1158503166835 |
13 | 5781a8a65221 |
14 | 2688386c4cad |
15 | 12568a2109eb |
hex | 91b21a38f29 |
10012133134121 has 2 divisors, whose sum is σ = 10012133134122. Its totient is φ = 10012133134120.
The previous prime is 10012133134109. The next prime is 10012133134123. The reversal of 10012133134121 is 12143133121001.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7461529296400 + 2550603837721 = 2731580^2 + 1597061^2 .
It is a cyclic number.
It is not a de Polignac number, because 10012133134121 - 238 = 9737255227177 is a prime.
Together with 10012133134123, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (10012133134123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5006066567060 + 5006066567061.
It is an arithmetic number, because the mean of its divisors is an integer number (5006066567061).
Almost surely, 210012133134121 is an apocalyptic number.
It is an amenable number.
10012133134121 is a deficient number, since it is larger than the sum of its proper divisors (1).
10012133134121 is an equidigital number, since it uses as much as digits as its factorization.
10012133134121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 23.
Adding to 10012133134121 its reverse (12143133121001), we get a palindrome (22155266255122).
The spelling of 10012133134121 in words is "ten trillion, twelve billion, one hundred thirty-three million, one hundred thirty-four thousand, one hundred twenty-one".
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