1001213320031 has 2 divisors, whose sum is σ = 1001213320032. Its totient is φ = 1001213320030.

The previous prime is 1001213319959. The next prime is 1001213320087. The reversal of 1001213320031 is 1300233121001.

It is a strong prime.

It is an emirp because it is prime and its reverse (1300233121001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1001213320031 - 2¹⁴ = 1001213303647 is a prime.

It is a super-2 number, since 2×1001213320031² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1001213319991 and 1001213320009.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1001213320631) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500606660015 + 500606660016.

It is an arithmetic number, because the mean of its divisors is an integer number (500606660016).

Almost surely, 2^{1001213320031} is an apocalyptic number.

1001213320031 is a deficient number, since it is larger than the sum of its proper divisors (1).

1001213320031 is an equidigital number, since it uses as much as digits as its factorization.

1001213320031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 1001213320031 its reverse (1300233121001), we get a palindrome (2301446441032).

The spelling of 1001213320031 in words is "one trillion, one billion, two hundred thirteen million, three hundred twenty thousand, thirty-one".