1001220023 has 4 divisors (see below), whose sum is σ = 1017633528. Its totient is φ = 984806520.

The previous prime is 1001220019. The next prime is 1001220043. The reversal of 1001220023 is 3200221001.

It is a happy number.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3200221001 = 401 ⋅7980601.

It is a cyclic number.

It is not a de Polignac number, because 1001220023 - 2² = 1001220019 is a prime.

It is a super-2 number, since 2×1001220023² = 2004883068912241058, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1001219986 and 1001220013.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1001220013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8206661 + ... + 8206782.

It is an arithmetic number, because the mean of its divisors is an integer number (254408382).

Almost surely, 2^1001220023 is an apocalyptic number.

1001220023 is a deficient number, since it is larger than the sum of its proper divisors (16413505).

1001220023 is an equidigital number, since it uses as much as digits as its factorization.

1001220023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16413504.

The product of its (nonzero) digits is 24, while the sum is 11.

The square root of 1001220023 is about 31642.0609790197. The cubic root of 1001220023 is about 1000.4065090613.

Adding to 1001220023 its reverse (3200221001), we get a palindrome (4201441024).

It can be divided in two parts, 10012 and 20023, that multiplied together give a triangular number (200470276 = T₂₀₀₂₃).

The spelling of 1001220023 in words is "one billion, one million, two hundred twenty thousand, twenty-three".