Base | Representation |
---|---|
bin | 10110110000111101111001… |
… | …100000001100110011000101 |
3 | 111010111120102210120201212200 |
4 | 112300331321200030303011 |
5 | 101110344344401334341 |
6 | 552535231014505113 |
7 | 30042402006435321 |
oct | 2660757140146305 |
9 | 433446383521780 |
10 | 100122021121221 |
11 | 299a1568824610 |
12 | b29039a365199 |
13 | 43b3609c91218 |
14 | 1aa1d08750981 |
15 | b8960be0adb6 |
hex | 5b0f7980ccc5 |
100122021121221 has 48 divisors (see below), whose sum is σ = 159013871565120. Its totient is φ = 60202017308160.
The previous prime is 100122021121193. The next prime is 100122021121229. The reversal of 100122021121221 is 122121120221001.
100122021121221 is a `hidden beast` number, since 1 + 0 + 0 + 1 + 220 + 211 + 212 + 21 = 666.
It is not a de Polignac number, because 100122021121221 - 210 = 100122021120197 is a prime.
It is a super-2 number, since 2×1001220211212212 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 100122021121194 and 100122021121203.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (100122021121229) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 5355421 + ... + 15130253.
It is an arithmetic number, because the mean of its divisors is an integer number (3312788990940).
Almost surely, 2100122021121221 is an apocalyptic number.
100122021121221 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
100122021121221 is a deficient number, since it is larger than the sum of its proper divisors (58891850443899).
100122021121221 is a wasteful number, since it uses less digits than its factorization.
100122021121221 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9775666 (or 9775663 counting only the distinct ones).
The product of its (nonzero) digits is 64, while the sum is 18.
Adding to 100122021121221 its reverse (122121120221001), we get a palindrome (222243141342222).
The spelling of 100122021121221 in words is "one hundred trillion, one hundred twenty-two billion, twenty-one million, one hundred twenty-one thousand, two hundred twenty-one".
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