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10012210020133 is a prime number
BaseRepresentation
bin1001000110110010011000…
…1110001011111100100101
31022110011021010112112122021
42101230212032023330211
52303020001231121013
633143313520103141
72052233616660526
oct221544616137445
938404233475567
1010012210020133
1132101775a1952
121158524a64ab1
135781bb9750c9
142688449ba84d
15125691d4ba8d
hex91b2638bf25

10012210020133 has 2 divisors, whose sum is σ = 10012210020134. Its totient is φ = 10012210020132.

The previous prime is 10012210020119. The next prime is 10012210020143. The reversal of 10012210020133 is 33102001221001.

10012210020133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9267263231524 + 744946788609 = 3044218^2 + 863103^2 .

It is a cyclic number.

It is not a de Polignac number, because 10012210020133 - 25 = 10012210020101 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10012210020143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5006105010066 + 5006105010067.

It is an arithmetic number, because the mean of its divisors is an integer number (5006105010067).

Almost surely, 210012210020133 is an apocalyptic number.

It is an amenable number.

10012210020133 is a deficient number, since it is larger than the sum of its proper divisors (1).

10012210020133 is an equidigital number, since it uses as much as digits as its factorization.

10012210020133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 10012210020133 its reverse (33102001221001), we get a palindrome (43114211241134).

The spelling of 10012210020133 in words is "ten trillion, twelve billion, two hundred ten million, twenty thousand, one hundred thirty-three".