100122121113281 has 2 divisors, whose sum is σ = 100122121113282. Its totient is φ = 100122121113280.

The previous prime is 100122121113239. The next prime is 100122121113283. The reversal of 100122121113281 is 182311121221001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 71930906101681 + 28191215011600 = 8481209^2 + 5309540^2 .

It is a cyclic number.

It is not a de Polignac number, because 100122121113281 - 2¹⁴ = 100122121096897 is a prime.

It is a super-2 number, since 2×100122121113281² (a number of 29 digits) contains 22 as substring.

Together with 100122121113283, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 100122121113281.

It is not a weakly prime, because it can be changed into another prime (100122121113283) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50061060556640 + 50061060556641.

It is an arithmetic number, because the mean of its divisors is an integer number (50061060556641).

Almost surely, 2^{100122121113281} is an apocalyptic number.

It is an amenable number.

100122121113281 is a deficient number, since it is larger than the sum of its proper divisors (1).

100122121113281 is an equidigital number, since it uses as much as digits as its factorization.

100122121113281 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 384, while the sum is 26.

Adding to 100122121113281 its reverse (182311121221001), we get a palindrome (282433242334282).

The spelling of 100122121113281 in words is "one hundred trillion, one hundred twenty-two billion, one hundred twenty-one million, one hundred thirteen thousand, two hundred eighty-one".