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100122310031 is a prime number
BaseRepresentation
bin101110100111111000…
…0010011010110001111
3100120102200210100001212
41131033300103112033
53120022302410111
6113555012325035
710143060410342
oct1351760232617
9316380710055
10100122310031
1139509485477
12174a291377b
139597c64c43
144bbb3bc459
15290ed4998b
hex174fc1358f

100122310031 has 2 divisors, whose sum is σ = 100122310032. Its totient is φ = 100122310030.

The previous prime is 100122310019. The next prime is 100122310049. The reversal of 100122310031 is 130013221001.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 100122310031 - 214 = 100122293647 is a prime.

It is a super-2 number, since 2×1001223100312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 100122309988 and 100122310015.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100122310531) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50061155015 + 50061155016.

It is an arithmetic number, because the mean of its divisors is an integer number (50061155016).

Almost surely, 2100122310031 is an apocalyptic number.

100122310031 is a deficient number, since it is larger than the sum of its proper divisors (1).

100122310031 is an equidigital number, since it uses as much as digits as its factorization.

100122310031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 100122310031 its reverse (130013221001), we get a palindrome (230135531032).

The spelling of 100122310031 in words is "one hundred billion, one hundred twenty-two million, three hundred ten thousand, thirty-one".