Base | Representation |
---|---|
bin | 11101001000111011000… |
… | …11001001011111100001 |
3 | 10112201022221222000201221 |
4 | 32210131203021133201 |
5 | 112401001110230103 |
6 | 2043542222255041 |
7 | 132223146132625 |
oct | 16443543113741 |
9 | 3481287860657 |
10 | 1001223133153 |
11 | 3566863a1a41 |
12 | 142063727481 |
13 | 735517cc579 |
14 | 36660a79185 |
15 | 1b09dd211bd |
hex | e91d8c97e1 |
1001223133153 has 2 divisors, whose sum is σ = 1001223133154. Its totient is φ = 1001223133152.
The previous prime is 1001223133111. The next prime is 1001223133171. The reversal of 1001223133153 is 3513313221001.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 863873584704 + 137349548449 = 929448^2 + 370607^2 .
It is a cyclic number.
It is not a de Polignac number, because 1001223133153 - 221 = 1001221036001 is a prime.
It is not a weakly prime, because it can be changed into another prime (1001223133103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500611566576 + 500611566577.
It is an arithmetic number, because the mean of its divisors is an integer number (500611566577).
Almost surely, 21001223133153 is an apocalyptic number.
It is an amenable number.
1001223133153 is a deficient number, since it is larger than the sum of its proper divisors (1).
1001223133153 is an equidigital number, since it uses as much as digits as its factorization.
1001223133153 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1620, while the sum is 25.
Adding to 1001223133153 its reverse (3513313221001), we get a palindrome (4514536354154).
The spelling of 1001223133153 in words is "one trillion, one billion, two hundred twenty-three million, one hundred thirty-three thousand, one hundred fifty-three".
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