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100122506302433 is a prime number
BaseRepresentation
bin10110110000111110010110…
…011011000001001111100001
3111010111121200121112111101012
4112300332112123001033201
5101110401343103134213
6552535351105550305
730042420020422646
oct2660762633011741
9433447617474335
10100122506302433
11299a179768a41a
12b2904b4945395
1343b36866582b4
141aa1d52d69dcd
15b896397e84a8
hex5b0f966c13e1

100122506302433 has 2 divisors, whose sum is σ = 100122506302434. Its totient is φ = 100122506302432.

The previous prime is 100122506302391. The next prime is 100122506302457. The reversal of 100122506302433 is 334203605221001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 97801478428369 + 2321027874064 = 9889463^2 + 1523492^2 .

It is an emirp because it is prime and its reverse (334203605221001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 100122506302433 - 224 = 100122489525217 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 100122506302433.

It is not a weakly prime, because it can be changed into another prime (100122506302733) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50061253151216 + 50061253151217.

It is an arithmetic number, because the mean of its divisors is an integer number (50061253151217).

Almost surely, 2100122506302433 is an apocalyptic number.

It is an amenable number.

100122506302433 is a deficient number, since it is larger than the sum of its proper divisors (1).

100122506302433 is an equidigital number, since it uses as much as digits as its factorization.

100122506302433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 25920, while the sum is 32.

The spelling of 100122506302433 in words is "one hundred trillion, one hundred twenty-two billion, five hundred six million, three hundred two thousand, four hundred thirty-three".