100123330230041 has 2 divisors, whose sum is σ = 100123330230042. Its totient is φ = 100123330230040.

The previous prime is 100123330229983. The next prime is 100123330230043. The reversal of 100123330230041 is 140032033321001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 97733075088016 + 2390255142025 = 9886004^2 + 1546045^2 .

It is a cyclic number.

It is not a de Polignac number, because 100123330230041 - 2²⁶ = 100123263121177 is a prime.

It is a super-3 number, since 3×100123330230041³ (a number of 43 digits) contains 333 as substring.

Together with 100123330230043, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 100123330229989 and 100123330230016.

It is not a weakly prime, because it can be changed into another prime (100123330230043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50061665115020 + 50061665115021.

It is an arithmetic number, because the mean of its divisors is an integer number (50061665115021).

Almost surely, 2^{100123330230041} is an apocalyptic number.

It is an amenable number.

100123330230041 is a deficient number, since it is larger than the sum of its proper divisors (1).

100123330230041 is an equidigital number, since it uses as much as digits as its factorization.

100123330230041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 100123330230041 its reverse (140032033321001), we get a palindrome (240155363551042).

The spelling of 100123330230041 in words is "one hundred trillion, one hundred twenty-three billion, three hundred thirty million, two hundred thirty thousand, forty-one".