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10012555129 is a prime number
BaseRepresentation
bin10010101001100101…
…10111011101111001
3221211210101111112011
421110302313131321
5131001203231004
64333311445521
7503056212553
oct112462673571
927753344464
1010012555129
11427890a955
121b352268a1
13c37495045
146adab04d3
153d903d004
hex254cb7779

10012555129 has 2 divisors, whose sum is σ = 10012555130. Its totient is φ = 10012555128.

The previous prime is 10012555123. The next prime is 10012555139. The reversal of 10012555129 is 92155521001.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9792092025 + 220463104 = 98955^2 + 14848^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10012555129 is a prime.

It is a super-2 number, since 2×100125551292 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 10012555129.

It is not a weakly prime, because it can be changed into another prime (10012555123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5006277564 + 5006277565.

It is an arithmetic number, because the mean of its divisors is an integer number (5006277565).

Almost surely, 210012555129 is an apocalyptic number.

It is an amenable number.

10012555129 is a deficient number, since it is larger than the sum of its proper divisors (1).

10012555129 is an equidigital number, since it uses as much as digits as its factorization.

10012555129 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4500, while the sum is 31.

The spelling of 10012555129 in words is "ten billion, twelve million, five hundred fifty-five thousand, one hundred twenty-nine".