Search a number
-
+
100130000197 is a prime number
BaseRepresentation
bin101110101000000110…
…1101000110101000101
3100120110020021000222211
41131100031220311011
53120031240001242
6113555445223421
710143212646553
oct1352015506505
9316406230884
10100130000197
1139512858187
12174a5401b71
139599728336
144bbc420bd3
152910868317
hex1750368d45

100130000197 has 2 divisors, whose sum is σ = 100130000198. Its totient is φ = 100130000196.

The previous prime is 100130000189. The next prime is 100130000237. The reversal of 100130000197 is 791000031001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 76088257281 + 24041742916 = 275841^2 + 155054^2 .

It is a cyclic number.

It is not a de Polignac number, because 100130000197 - 23 = 100130000189 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100130000137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50065000098 + 50065000099.

It is an arithmetic number, because the mean of its divisors is an integer number (50065000099).

Almost surely, 2100130000197 is an apocalyptic number.

It is an amenable number.

100130000197 is a deficient number, since it is larger than the sum of its proper divisors (1).

100130000197 is an equidigital number, since it uses as much as digits as its factorization.

100130000197 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 189, while the sum is 22.

Adding to 100130000197 its reverse (791000031001), we get a palindrome (891130031198).

The spelling of 100130000197 in words is "one hundred billion, one hundred thirty million, one hundred ninety-seven", and thus it is an aban number.