10013002211 has 2 divisors, whose sum is σ = 10013002212. Its totient is φ = 10013002210.

The previous prime is 10013002169. The next prime is 10013002213. The reversal of 10013002211 is 11220031001.

It is a strong prime.

It is an emirp because it is prime and its reverse (11220031001) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10013002211 is a prime.

Together with 10013002213, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 10013002192 and 10013002201.

It is not a weakly prime, because it can be changed into another prime (10013002213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5006501105 + 5006501106.

It is an arithmetic number, because the mean of its divisors is an integer number (5006501106).

Almost surely, 2^10013002211 is an apocalyptic number.

10013002211 is a deficient number, since it is larger than the sum of its proper divisors (1).

10013002211 is an equidigital number, since it uses as much as digits as its factorization.

10013002211 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 11.

Adding to 10013002211 its reverse (11220031001), we get a palindrome (21233033212).

The spelling of 10013002211 in words is "ten billion, thirteen million, two thousand, two hundred eleven".