Base | Representation |
---|---|
bin | 11101001001000100011… |
… | …00100100101101011001 |
3 | 10112201112101200020001211 |
4 | 32210202030210231121 |
5 | 112401131040221101 |
6 | 2043554045343121 |
7 | 132225113634406 |
oct | 16444214445531 |
9 | 3481471606054 |
10 | 1001301101401 |
11 | 356716405707 |
12 | 142085867aa1 |
13 | 735649cac23 |
14 | 3666b1732ad |
15 | 1b0a5ac2c51 |
hex | e922324b59 |
1001301101401 has 2 divisors, whose sum is σ = 1001301101402. Its totient is φ = 1001301101400.
The previous prime is 1001301101389. The next prime is 1001301101417. The reversal of 1001301101401 is 1041011031001.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 671250851401 + 330050250000 = 819299^2 + 574500^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1001301101401 is a prime.
It is not a weakly prime, because it can be changed into another prime (1001301101501) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500650550700 + 500650550701.
It is an arithmetic number, because the mean of its divisors is an integer number (500650550701).
Almost surely, 21001301101401 is an apocalyptic number.
It is an amenable number.
1001301101401 is a deficient number, since it is larger than the sum of its proper divisors (1).
1001301101401 is an equidigital number, since it uses as much as digits as its factorization.
1001301101401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12, while the sum is 13.
Adding to 1001301101401 its reverse (1041011031001), we get a palindrome (2042312132402).
The spelling of 1001301101401 in words is "one trillion, one billion, three hundred one million, one hundred one thousand, four hundred one".
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