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1001301130213 is a prime number
BaseRepresentation
bin11101001001000100011…
…00101011101111100101
310112201112101201200120221
432210202030223233211
5112401131042131323
62043554050124341
7132225114114406
oct16444214535745
93481471650527
101001301130213
1135671642531a
121420858806b1
1373564a0b087
143666b17d9ad
151b0a5acb55d
hexe92232bbe5

1001301130213 has 2 divisors, whose sum is σ = 1001301130214. Its totient is φ = 1001301130212.

The previous prime is 1001301130201. The next prime is 1001301130241. The reversal of 1001301130213 is 3120311031001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 578844029124 + 422457101089 = 760818^2 + 649967^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1001301130213 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1001301100213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500650565106 + 500650565107.

It is an arithmetic number, because the mean of its divisors is an integer number (500650565107).

Almost surely, 21001301130213 is an apocalyptic number.

It is an amenable number.

1001301130213 is a deficient number, since it is larger than the sum of its proper divisors (1).

1001301130213 is an equidigital number, since it uses as much as digits as its factorization.

1001301130213 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 1001301130213 its reverse (3120311031001), we get a palindrome (4121612161214).

The spelling of 1001301130213 in words is "one trillion, one billion, three hundred one million, one hundred thirty thousand, two hundred thirteen".