Base | Representation |
---|---|
bin | 101110101000001000… |
… | …1011100111110111111 |
3 | 100120110022010211211000 |
4 | 1131100101130332333 |
5 | 3120032014002010 |
6 | 113555522501343 |
7 | 10143224313306 |
oct | 1352021347677 |
9 | 316408124730 |
10 | 100131000255 |
11 | 39513380580 |
12 | 174a5804853 |
13 | 95999b85a0 |
14 | 4bbc60143d |
15 | 29109b47c0 |
hex | 175045cfbf |
100131000255 has 128 divisors (see below), whose sum is σ = 220139136000. Its totient is φ = 42455093760.
The previous prime is 100131000253. The next prime is 100131000283. The reversal of 100131000255 is 552000131001.
100131000255 is a `hidden beast` number, since 100 + 1 + 310 + 0 + 0 + 255 = 666.
It is not a de Polignac number, because 100131000255 - 21 = 100131000253 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (100131000251) by changing a digit.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 230301 + ... + 503289.
It is an arithmetic number, because the mean of its divisors is an integer number (1719837000).
Almost surely, 2100131000255 is an apocalyptic number.
100131000255 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
100131000255 is an abundant number, since it is smaller than the sum of its proper divisors (120008135745).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
100131000255 is a wasteful number, since it uses less digits than its factorization.
100131000255 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 273046 (or 273040 counting only the distinct ones).
The product of its (nonzero) digits is 150, while the sum is 18.
Adding to 100131000255 its reverse (552000131001), we get a palindrome (652131131256).
The spelling of 100131000255 in words is "one hundred billion, one hundred thirty-one million, two hundred fifty-five", and thus it is an aban number.
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