Base | Representation |
---|---|
bin | 10010101001101001… |
… | …11111000000100011 |
3 | 221211211102201002022 |
4 | 21110310333000203 |
5 | 131001324012212 |
6 | 4333331412055 |
7 | 503064014264 |
oct | 112464770043 |
9 | 27754381068 |
10 | 10013110307 |
11 | 4279159a82 |
12 | 1b3545402b |
13 | c3762a955 |
14 | 6adbb696b |
15 | 3d90ec772 |
hex | 254d3f023 |
10013110307 has 2 divisors, whose sum is σ = 10013110308. Its totient is φ = 10013110306.
The previous prime is 10013110243. The next prime is 10013110309. The reversal of 10013110307 is 70301131001.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10013110307 - 26 = 10013110243 is a prime.
Together with 10013110309, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (10013110309) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5006555153 + 5006555154.
It is an arithmetic number, because the mean of its divisors is an integer number (5006555154).
Almost surely, 210013110307 is an apocalyptic number.
10013110307 is a deficient number, since it is larger than the sum of its proper divisors (1).
10013110307 is an equidigital number, since it uses as much as digits as its factorization.
10013110307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 63, while the sum is 17.
Adding to 10013110307 its reverse (70301131001), we get a palindrome (80314241308).
The spelling of 10013110307 in words is "ten billion, thirteen million, one hundred ten thousand, three hundred seven".
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