Base | Representation |
---|---|
bin | 11101001001000101100… |
… | …11001110010001001111 |
3 | 10112201120002201222011001 |
4 | 32210202303032101033 |
5 | 112401141133424403 |
6 | 2043555050441131 |
7 | 132225266023036 |
oct | 16444263162117 |
9 | 3481502658131 |
10 | 1001311233103 |
11 | 3567210a5815 |
12 | 1420891331a7 |
13 | 73566b3770c |
14 | 3666c64d71d |
15 | 1b0a6924c1d |
hex | e922cce44f |
1001311233103 has 2 divisors, whose sum is σ = 1001311233104. Its totient is φ = 1001311233102.
The previous prime is 1001311232951. The next prime is 1001311233113. The reversal of 1001311233103 is 3013321131001.
1001311233103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is an emirp because it is prime and its reverse (3013321131001) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1001311233103 - 213 = 1001311224911 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1001311233113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500655616551 + 500655616552.
It is an arithmetic number, because the mean of its divisors is an integer number (500655616552).
Almost surely, 21001311233103 is an apocalyptic number.
1001311233103 is a deficient number, since it is larger than the sum of its proper divisors (1).
1001311233103 is an equidigital number, since it uses as much as digits as its factorization.
1001311233103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 1001311233103 its reverse (3013321131001), we get a palindrome (4014632364104).
The spelling of 1001311233103 in words is "one trillion, one billion, three hundred eleven million, two hundred thirty-three thousand, one hundred three".
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