100131211121 has 2 divisors, whose sum is σ = 100131211122. Its totient is φ = 100131211120.

The previous prime is 100131211093. The next prime is 100131211123. The reversal of 100131211121 is 121112131001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 59704479025 + 40426732096 = 244345^2 + 201064^2 .

It is an emirp because it is prime and its reverse (121112131001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 100131211121 - 2¹⁸ = 100130948977 is a prime.

Together with 100131211123, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 100131211096 and 100131211105.

It is not a weakly prime, because it can be changed into another prime (100131211123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50065605560 + 50065605561.

It is an arithmetic number, because the mean of its divisors is an integer number (50065605561).

Almost surely, 2^100131211121 is an apocalyptic number.

It is an amenable number.

100131211121 is a deficient number, since it is larger than the sum of its proper divisors (1).

100131211121 is an equidigital number, since it uses as much as digits as its factorization.

100131211121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 14.

Adding to 100131211121 its reverse (121112131001), we get a palindrome (221243342122).

The spelling of 100131211121 in words is "one hundred billion, one hundred thirty-one million, two hundred eleven thousand, one hundred twenty-one".