Base | Representation |
---|---|
bin | 1001000110110110000111… |
… | …0100111011001111111111 |
3 | 1022110020211211020100210121 |
4 | 2101231201310323033333 |
5 | 2303024023231443403 |
6 | 33144001041515411 |
7 | 2052300451635436 |
oct | 221554164731777 |
9 | 38406754210717 |
10 | 10013210031103 |
11 | 32106400229a4 |
12 | 1158763942b67 |
13 | 57831abb7286 |
14 | 2688db72c11d |
15 | 1256eea313bd |
hex | 91b61d3b3ff |
10013210031103 has 2 divisors, whose sum is σ = 10013210031104. Its totient is φ = 10013210031102.
The previous prime is 10013210031091. The next prime is 10013210031113. The reversal of 10013210031103 is 30113001231001.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10013210031103 - 237 = 9875771077631 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10013210031113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5006605015551 + 5006605015552.
It is an arithmetic number, because the mean of its divisors is an integer number (5006605015552).
Almost surely, 210013210031103 is an apocalyptic number.
10013210031103 is a deficient number, since it is larger than the sum of its proper divisors (1).
10013210031103 is an equidigital number, since it uses as much as digits as its factorization.
10013210031103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 10013210031103 its reverse (30113001231001), we get a palindrome (40126211262104).
The spelling of 10013210031103 in words is "ten trillion, thirteen billion, two hundred ten million, thirty-one thousand, one hundred three".
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