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100132203000103 is a prime number
BaseRepresentation
bin10110110001000111011000…
…011000111111000100100111
3111010112112201101120202220221
4112301013120120333010213
5101111031222432000403
6552544033215505211
730043212223122361
oct2661073030770447
9433475641522827
10100132203000103
11299a591317494a
12b292360228207
1343b457055c821
141aa25d2ad9d31
15b89a05c43dbd
hex5b11d863f127

100132203000103 has 2 divisors, whose sum is σ = 100132203000104. Its totient is φ = 100132203000102.

The previous prime is 100132203000007. The next prime is 100132203000107. The reversal of 100132203000103 is 301000302231001.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 100132203000103 - 237 = 99994764046631 is a prime.

It is a super-4 number, since 4×1001322030001034 (a number of 57 digits) contains 4444 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100132203000107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50066101500051 + 50066101500052.

It is an arithmetic number, because the mean of its divisors is an integer number (50066101500052).

Almost surely, 2100132203000103 is an apocalyptic number.

100132203000103 is a deficient number, since it is larger than the sum of its proper divisors (1).

100132203000103 is an equidigital number, since it uses as much as digits as its factorization.

100132203000103 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108, while the sum is 16.

Adding to 100132203000103 its reverse (301000302231001), we get a palindrome (401132505231104).

The spelling of 100132203000103 in words is "one hundred trillion, one hundred thirty-two billion, two hundred three million, one hundred three", and thus it is an aban number.