Base | Representation |
---|---|
bin | 1001000110110110010001… |
… | …0010000001011010010101 |
3 | 1022110020221200201121200011 |
4 | 2101231210102001122111 |
5 | 2303024114302303244 |
6 | 33144005112320221 |
7 | 2052301461655225 |
oct | 221554422013225 |
9 | 38406850647604 |
10 | 10013251212949 |
11 | 32106612a0486 |
12 | 11587756a3071 |
13 | 5783265a5a2a |
14 | 268902dac085 |
15 | 125703468434 |
hex | 91b64481695 |
10013251212949 has 2 divisors, whose sum is σ = 10013251212950. Its totient is φ = 10013251212948.
The previous prime is 10013251212823. The next prime is 10013251212973. The reversal of 10013251212949 is 94921215231001.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9966964702500 + 46286510449 = 3157050^2 + 215143^2 .
It is a cyclic number.
It is not a de Polignac number, because 10013251212949 - 211 = 10013251210901 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10013251212989) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5006625606474 + 5006625606475.
It is an arithmetic number, because the mean of its divisors is an integer number (5006625606475).
Almost surely, 210013251212949 is an apocalyptic number.
It is an amenable number.
10013251212949 is a deficient number, since it is larger than the sum of its proper divisors (1).
10013251212949 is an equidigital number, since it uses as much as digits as its factorization.
10013251212949 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 38880, while the sum is 40.
The spelling of 10013251212949 in words is "ten trillion, thirteen billion, two hundred fifty-one million, two hundred twelve thousand, nine hundred forty-nine".
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