Base | Representation |
---|---|
bin | 10110110001001000011101… |
… | …001101101100000001110001 |
3 | 111010112122200212021220022222 |
4 | 112301020131031230001301 |
5 | 101111041104030311132 |
6 | 552544343544210425 |
7 | 30043252643456435 |
oct | 2661103515540161 |
9 | 433478625256288 |
10 | 100133357666417 |
11 | 299a6355a27829 |
12 | b292622a69a15 |
13 | 43b46c584082a |
14 | 1aa26a21c89c5 |
15 | b89a722c7412 |
hex | 5b121d36c071 |
100133357666417 has 2 divisors, whose sum is σ = 100133357666418. Its totient is φ = 100133357666416.
The previous prime is 100133357666401. The next prime is 100133357666467. The reversal of 100133357666417 is 714666753331001.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 99427302312976 + 706055353441 = 9971324^2 + 840271^2 .
It is a cyclic number.
It is not a de Polignac number, because 100133357666417 - 24 = 100133357666401 is a prime.
It is a super-3 number, since 3×1001333576664173 (a number of 43 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (100133357666467) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50066678833208 + 50066678833209.
It is an arithmetic number, because the mean of its divisors is an integer number (50066678833209).
Almost surely, 2100133357666417 is an apocalyptic number.
It is an amenable number.
100133357666417 is a deficient number, since it is larger than the sum of its proper divisors (1).
100133357666417 is an equidigital number, since it uses as much as digits as its factorization.
100133357666417 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5715360, while the sum is 53.
The spelling of 100133357666417 in words is "one hundred trillion, one hundred thirty-three billion, three hundred fifty-seven million, six hundred sixty-six thousand, four hundred seventeen".
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