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100135221534431 is a prime number
BaseRepresentation
bin10110110001001010001100…
…010011110001111011011111
3111010112211111202111012120122
4112301022030103301323133
5101111103413203100211
6552545252525305155
730043350065211116
oct2661121423617337
9433484452435518
10100135221534431
11299a7122044416
12b292a631051bb
1343b4931a33305
141aa27db968c7d
15b89b30c496db
hex5b128c4f1edf

100135221534431 has 2 divisors, whose sum is σ = 100135221534432. Its totient is φ = 100135221534430.

The previous prime is 100135221534373. The next prime is 100135221534493. The reversal of 100135221534431 is 134435122531001.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 100135221534431 - 214 = 100135221518047 is a prime.

It is a super-3 number, since 3×1001352215344313 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Sophie Germain prime.

It is a junction number, because it is equal to n+sod(n) for n = 100135221534391 and 100135221534400.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100135221534731) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50067610767215 + 50067610767216.

It is an arithmetic number, because the mean of its divisors is an integer number (50067610767216).

Almost surely, 2100135221534431 is an apocalyptic number.

100135221534431 is a deficient number, since it is larger than the sum of its proper divisors (1).

100135221534431 is an equidigital number, since it uses as much as digits as its factorization.

100135221534431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 43200, while the sum is 35.

The spelling of 100135221534431 in words is "one hundred trillion, one hundred thirty-five billion, two hundred twenty-one million, five hundred thirty-four thousand, four hundred thirty-one".