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1001429696753 is a prime number
BaseRepresentation
bin11101001001010011101…
…11001000000011110001
310112201212100122112201122
432210221313020003301
5112401412000244003
62044014521512025
7132231234655103
oct16445167100361
93481770575648
101001429696753
11356781a58262
12142100942615
1373585544255
1436680289573
151b0b2025238
hexe929dc80f1

1001429696753 has 2 divisors, whose sum is σ = 1001429696754. Its totient is φ = 1001429696752.

The previous prime is 1001429696713. The next prime is 1001429696759. The reversal of 1001429696753 is 3576969241001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 550850449249 + 450579247504 = 742193^2 + 671252^2 .

It is a cyclic number.

It is not a de Polignac number, because 1001429696753 - 220 = 1001428648177 is a prime.

It is a super-2 number, since 2×10014296967532 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1001429696695 and 1001429696704.

It is not a weakly prime, because it can be changed into another prime (1001429696759) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500714848376 + 500714848377.

It is an arithmetic number, because the mean of its divisors is an integer number (500714848377).

Almost surely, 21001429696753 is an apocalyptic number.

It is an amenable number.

1001429696753 is a deficient number, since it is larger than the sum of its proper divisors (1).

1001429696753 is an equidigital number, since it uses as much as digits as its factorization.

1001429696753 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2449440, while the sum is 53.

The spelling of 1001429696753 in words is "one trillion, one billion, four hundred twenty-nine million, six hundred ninety-six thousand, seven hundred fifty-three".