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10014310213 is a prime number
BaseRepresentation
bin10010101001110011…
…00011111101000101
3221211220200200001021
421110321203331011
5131002130411323
64333413231141
7503110142455
oct112471437505
927756620037
1010014310213
1142798a9536
121b359324b1
13c3795ab5b
146b0009d65
153d928805d
hex254e63f45

10014310213 has 2 divisors, whose sum is σ = 10014310214. Its totient is φ = 10014310212.

The previous prime is 10014310199. The next prime is 10014310253. The reversal of 10014310213 is 31201341001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6156285444 + 3858024769 = 78462^2 + 62113^2 .

It is a cyclic number.

It is not a de Polignac number, because 10014310213 - 25 = 10014310181 is a prime.

It is a super-2 number, since 2×100143102132 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10014310253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5007155106 + 5007155107.

It is an arithmetic number, because the mean of its divisors is an integer number (5007155107).

Almost surely, 210014310213 is an apocalyptic number.

It is an amenable number.

10014310213 is a deficient number, since it is larger than the sum of its proper divisors (1).

10014310213 is an equidigital number, since it uses as much as digits as its factorization.

10014310213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 10014310213 its reverse (31201341001), we get a palindrome (41215651214).

The spelling of 10014310213 in words is "ten billion, fourteen million, three hundred ten thousand, two hundred thirteen".