Base | Representation |
---|---|
bin | 11101001001010100111… |
… | …11111110001101101011 |
3 | 10112201220002210112202121 |
4 | 32210222133332031223 |
5 | 112401422220414311 |
6 | 2044015543212111 |
7 | 132231424662403 |
oct | 16445237761553 |
9 | 3481802715677 |
10 | 1001440404331 |
11 | 356788000aa4 |
12 | 142104447037 |
13 | 73587822bb3 |
14 | 36681875803 |
15 | 1b0b2e3cb71 |
hex | e92a7fe36b |
1001440404331 has 2 divisors, whose sum is σ = 1001440404332. Its totient is φ = 1001440404330.
The previous prime is 1001440404271. The next prime is 1001440404337. The reversal of 1001440404331 is 1334040441001.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1001440404331 - 27 = 1001440404203 is a prime.
It is a super-2 number, since 2×10014404043312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1001440404296 and 1001440404305.
It is not a weakly prime, because it can be changed into another prime (1001440404337) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500720202165 + 500720202166.
It is an arithmetic number, because the mean of its divisors is an integer number (500720202166).
Almost surely, 21001440404331 is an apocalyptic number.
1001440404331 is a deficient number, since it is larger than the sum of its proper divisors (1).
1001440404331 is an equidigital number, since it uses as much as digits as its factorization.
1001440404331 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 1001440404331 its reverse (1334040441001), we get a palindrome (2335480845332).
The spelling of 1001440404331 in words is "one trillion, one billion, four hundred forty million, four hundred four thousand, three hundred thirty-one".
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