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100172000473 = 472131319159
BaseRepresentation
bin101110101001010110…
…1110110110011011001
3100120120011021212112121
41131102231312303121
53120123013003343
6114003545341241
710144232645416
oct1352255666331
9316504255477
10100172000473
1139534534656
12174b7497821
1395a534247c
144bc3c3510d
1529143b2aed
hex1752b76cd9

100172000473 has 4 divisors (see below), whose sum is σ = 102303319680. Its totient is φ = 98040681268.

The previous prime is 100172000471. The next prime is 100172000479. The reversal of 100172000473 is 374000271001.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 100172000473 - 21 = 100172000471 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (100172000471) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1065659533 + ... + 1065659626.

It is an arithmetic number, because the mean of its divisors is an integer number (25575829920).

Almost surely, 2100172000473 is an apocalyptic number.

It is an amenable number.

100172000473 is a deficient number, since it is larger than the sum of its proper divisors (2131319207).

100172000473 is an equidigital number, since it uses as much as digits as its factorization.

100172000473 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2131319206.

The product of its (nonzero) digits is 1176, while the sum is 25.

Adding to 100172000473 its reverse (374000271001), we get a palindrome (474172271474).

The spelling of 100172000473 in words is "one hundred billion, one hundred seventy-two million, four hundred seventy-three", and thus it is an aban number.

Divisors: 1 47 2131319159 100172000473