100200120133 has 2 divisors, whose sum is σ = 100200120134. Its totient is φ = 100200120132.

The previous prime is 100200120107. The next prime is 100200120227. The reversal of 100200120133 is 331021002001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 95881264609 + 4318855524 = 309647^2 + 65718^2 .

It is an emirp because it is prime and its reverse (331021002001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 100200120133 - 2⁵ = 100200120101 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100200120833) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50100060066 + 50100060067.

It is an arithmetic number, because the mean of its divisors is an integer number (50100060067).

Almost surely, 2^100200120133 is an apocalyptic number.

It is an amenable number.

100200120133 is a deficient number, since it is larger than the sum of its proper divisors (1).

100200120133 is an equidigital number, since it uses as much as digits as its factorization.

100200120133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36, while the sum is 13.

Adding to 100200120133 its reverse (331021002001), we get a palindrome (431221122134).

The spelling of 100200120133 in words is "one hundred billion, two hundred million, one hundred twenty thousand, one hundred thirty-three".