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100201111313 is a prime number
BaseRepresentation
bin101110101010001110…
…0111001111100010001
3100120122012001212002212
41131110130321330101
53120202441030223
6114010505321505
710145035251602
oct1352434717421
9316565055085
10100201111313
1139549a07aa6
1217505196295
1395ab395814
144bc7a51da9
152916c13278
hex1754739f11

100201111313 has 2 divisors, whose sum is σ = 100201111314. Its totient is φ = 100201111312.

The previous prime is 100201111279. The next prime is 100201111343. The reversal of 100201111313 is 313111102001.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 88656253504 + 11544857809 = 297752^2 + 107447^2 .

It is an emirp because it is prime and its reverse (313111102001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 100201111313 - 224 = 100184334097 is a prime.

It is not a weakly prime, because it can be changed into another prime (100201111343) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50100555656 + 50100555657.

It is an arithmetic number, because the mean of its divisors is an integer number (50100555657).

Almost surely, 2100201111313 is an apocalyptic number.

It is an amenable number.

100201111313 is a deficient number, since it is larger than the sum of its proper divisors (1).

100201111313 is an equidigital number, since it uses as much as digits as its factorization.

100201111313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18, while the sum is 14.

Adding to 100201111313 its reverse (313111102001), we get a palindrome (413312213314).

The spelling of 100201111313 in words is "one hundred billion, two hundred one million, one hundred eleven thousand, three hundred thirteen".