Base | Representation |
---|---|
bin | 1001000111001111110100… |
… | …1010110101011000001001 |
3 | 1022110220122210000120111202 |
4 | 2101303331022311120021 |
5 | 2303132141432204433 |
6 | 33151101530033545 |
7 | 2052633460662503 |
oct | 221637512653011 |
9 | 38426583016452 |
10 | 10020111209993 |
11 | 3213561610825 |
12 | 1159b6ab788b5 |
13 | 578b7a8a0191 |
14 | 268d940c2d73 |
15 | 1259a5829ee8 |
hex | 91cfd2b5609 |
10020111209993 has 2 divisors, whose sum is σ = 10020111209994. Its totient is φ = 10020111209992.
The previous prime is 10020111209923. The next prime is 10020111210077. The reversal of 10020111209993 is 39990211102001.
10020111209993 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9979198866169 + 40912343824 = 3158987^2 + 202268^2 .
It is an emirp because it is prime and its reverse (39990211102001) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10020111209993 - 218 = 10020110947849 is a prime.
It is not a weakly prime, because it can be changed into another prime (10020111209923) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5010055604996 + 5010055604997.
It is an arithmetic number, because the mean of its divisors is an integer number (5010055604997).
Almost surely, 210020111209993 is an apocalyptic number.
It is an amenable number.
10020111209993 is a deficient number, since it is larger than the sum of its proper divisors (1).
10020111209993 is an equidigital number, since it uses as much as digits as its factorization.
10020111209993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8748, while the sum is 38.
The spelling of 10020111209993 in words is "ten trillion, twenty billion, one hundred eleven million, two hundred nine thousand, nine hundred ninety-three".
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