Base | Representation |
---|---|
bin | 11101001010011001001… |
… | …00011110011010100011 |
3 | 10112210100221101010112101 |
4 | 32211030210132122203 |
5 | 112404110033311042 |
6 | 2044152402511231 |
7 | 132251535361561 |
oct | 16451444363243 |
9 | 3483327333471 |
10 | 1002012010147 |
11 | 356a507259a5 |
12 | 142243965517 |
13 | 736490896a5 |
14 | 366d774aa31 |
15 | 1b0e81ec6b7 |
hex | e94c91e6a3 |
1002012010147 has 2 divisors, whose sum is σ = 1002012010148. Its totient is φ = 1002012010146.
The previous prime is 1002012010121. The next prime is 1002012010151. The reversal of 1002012010147 is 7410102102001.
1002012010147 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1002012010147 - 231 = 999864526499 is a prime.
It is not a weakly prime, because it can be changed into another prime (1002012010247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 501006005073 + 501006005074.
It is an arithmetic number, because the mean of its divisors is an integer number (501006005074).
Almost surely, 21002012010147 is an apocalyptic number.
1002012010147 is a deficient number, since it is larger than the sum of its proper divisors (1).
1002012010147 is an equidigital number, since it uses as much as digits as its factorization.
1002012010147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 112, while the sum is 19.
Adding to 1002012010147 its reverse (7410102102001), we get a palindrome (8412114112148).
The spelling of 1002012010147 in words is "one trillion, two billion, twelve million, ten thousand, one hundred forty-seven".
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