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1002012020033 is a prime number
BaseRepresentation
bin11101001010011001001…
…00100000110101000001
310112210100221101122002112
432211030210200311001
5112404110034120113
62044152403025105
7132251535432443
oct16451444406501
93483327348075
101002012020033
11356a50732372
1214224396b195
137364909103b
14366d7750493
151b0e82005a8
hexe94c920d41

1002012020033 has 2 divisors, whose sum is σ = 1002012020034. Its totient is φ = 1002012020032.

The previous prime is 1002012020029. The next prime is 1002012020057. The reversal of 1002012020033 is 3300202102001.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 757608345649 + 244403674384 = 870407^2 + 494372^2 .

It is a cyclic number.

It is not a de Polignac number, because 1002012020033 - 22 = 1002012020029 is a prime.

It is a super-2 number, since 2×10020120200332 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1002012020833) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 501006010016 + 501006010017.

It is an arithmetic number, because the mean of its divisors is an integer number (501006010017).

Almost surely, 21002012020033 is an apocalyptic number.

It is an amenable number.

1002012020033 is a deficient number, since it is larger than the sum of its proper divisors (1).

1002012020033 is an equidigital number, since it uses as much as digits as its factorization.

1002012020033 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 14.

Adding to 1002012020033 its reverse (3300202102001), we get a palindrome (4302214122034).

The spelling of 1002012020033 in words is "one trillion, two billion, twelve million, twenty thousand, thirty-three".