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100201202111981 is a prime number
BaseRepresentation
bin10110110010000111101001…
…000011101101010111101101
3111010210010211001120211102002
4112302013221003231113231
5101113144030220040411
6553035444034142045
730051204124652015
oct2662075103552755
9433703731524362
10100201202111981
1129a22100396953
12b2a37b7a21925
1343bac18518989
141aa5a9a812c45
15b8b6e354a33b
hex5b21e90ed5ed

100201202111981 has 2 divisors, whose sum is σ = 100201202111982. Its totient is φ = 100201202111980.

The previous prime is 100201202111971. The next prime is 100201202112017. The reversal of 100201202111981 is 189111202102001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 67832783156356 + 32368418955625 = 8236066^2 + 5689325^2 .

It is a cyclic number.

It is not a de Polignac number, because 100201202111981 - 222 = 100201197917677 is a prime.

It is a super-2 number, since 2×1002012021119812 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100201202111971) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50100601055990 + 50100601055991.

It is an arithmetic number, because the mean of its divisors is an integer number (50100601055991).

Almost surely, 2100201202111981 is an apocalyptic number.

It is an amenable number.

100201202111981 is a deficient number, since it is larger than the sum of its proper divisors (1).

100201202111981 is an equidigital number, since it uses as much as digits as its factorization.

100201202111981 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576, while the sum is 29.

Adding to 100201202111981 its reverse (189111202102001), we get a palindrome (289312404213982).

The spelling of 100201202111981 in words is "one hundred trillion, two hundred one billion, two hundred two million, one hundred eleven thousand, nine hundred eighty-one".