100201243340137 has 2 divisors, whose sum is σ = 100201243340138. Its totient is φ = 100201243340136.

The previous prime is 100201243340111. The next prime is 100201243340167. The reversal of 100201243340137 is 731043342102001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 98853127285081 + 1348116055056 = 9942491^2 + 1161084^2 .

It is an emirp because it is prime and its reverse (731043342102001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 100201243340137 - 2²³ = 100201234951529 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 100201243340099 and 100201243340108.

It is not a weakly prime, because it can be changed into another prime (100201243340167) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50100621670068 + 50100621670069.

It is an arithmetic number, because the mean of its divisors is an integer number (50100621670069).

Almost surely, 2^{100201243340137} is an apocalyptic number.

It is an amenable number.

100201243340137 is a deficient number, since it is larger than the sum of its proper divisors (1).

100201243340137 is an equidigital number, since it uses as much as digits as its factorization.

100201243340137 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12096, while the sum is 31.

Adding to 100201243340137 its reverse (731043342102001), we get a palindrome (831244585442138).

The spelling of 100201243340137 in words is "one hundred trillion, two hundred one billion, two hundred forty-three million, three hundred forty thousand, one hundred thirty-seven".