100201243340111 has 2 divisors, whose sum is σ = 100201243340112. Its totient is φ = 100201243340110.

The previous prime is 100201243340083. The next prime is 100201243340137. The reversal of 100201243340111 is 111043342102001.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-100201243340111 is a prime.

It is a super-3 number, since 3×100201243340111³ (a number of 43 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100201243340911) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50100621670055 + 50100621670056.

It is an arithmetic number, because the mean of its divisors is an integer number (50100621670056).

Almost surely, 2^{100201243340111} is an apocalyptic number.

100201243340111 is a deficient number, since it is larger than the sum of its proper divisors (1).

100201243340111 is an equidigital number, since it uses as much as digits as its factorization.

100201243340111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 100201243340111 its reverse (111043342102001), we get a palindrome (211244585442112).

The spelling of 100201243340111 in words is "one hundred trillion, two hundred one billion, two hundred forty-three million, three hundred forty thousand, one hundred eleven".