10020130013 has 2 divisors, whose sum is σ = 10020130014. Its totient is φ = 10020130012.

The previous prime is 10020130009. The next prime is 10020130037. The reversal of 10020130013 is 31003102001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9737150329 + 282979684 = 98677^2 + 16822^2 .

It is a cyclic number.

It is not a de Polignac number, because 10020130013 - 2² = 10020130009 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 10020129976 and 10020130003.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10020130213) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5010065006 + 5010065007.

It is an arithmetic number, because the mean of its divisors is an integer number (5010065007).

Almost surely, 2^10020130013 is an apocalyptic number.

It is an amenable number.

10020130013 is a deficient number, since it is larger than the sum of its proper divisors (1).

10020130013 is an equidigital number, since it uses as much as digits as its factorization.

10020130013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18, while the sum is 11.

Adding to 10020130013 its reverse (31003102001), we get a palindrome (41023232014).

The spelling of 10020130013 in words is "ten billion, twenty million, one hundred thirty thousand, thirteen".