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10020130311151 is a prime number
BaseRepresentation
bin1001000111001111111001…
…0011101100101111101111
31022110220201002222000101001
42101303332103230233233
52303132211324424101
633151103451301131
72052634112226142
oct221637623545757
938426632860331
1010020130311151
113213571377804
121159b7544a7a7
13578b8182a43c
14268d96856059
151259a734e901
hex91cfe4ecbef

10020130311151 has 2 divisors, whose sum is σ = 10020130311152. Its totient is φ = 10020130311150.

The previous prime is 10020130311097. The next prime is 10020130311157. The reversal of 10020130311151 is 15111303102001.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10020130311151 - 221 = 10020128213999 is a prime.

It is a super-2 number, since 2×100201303111512 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10020130311157) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5010065155575 + 5010065155576.

It is an arithmetic number, because the mean of its divisors is an integer number (5010065155576).

Almost surely, 210020130311151 is an apocalyptic number.

10020130311151 is a deficient number, since it is larger than the sum of its proper divisors (1).

10020130311151 is an equidigital number, since it uses as much as digits as its factorization.

10020130311151 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 90, while the sum is 19.

Adding to 10020130311151 its reverse (15111303102001), we get a palindrome (25131433413152).

The spelling of 10020130311151 in words is "ten trillion, twenty billion, one hundred thirty million, three hundred eleven thousand, one hundred fifty-one".