100201411211051 has 2 divisors, whose sum is σ = 100201411211052. Its totient is φ = 100201411211050.

The previous prime is 100201411211021. The next prime is 100201411211053. The reversal of 100201411211051 is 150112114102001.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 100201411211051 - 2³⁴ = 100184231341867 is a prime.

It is a super-3 number, since 3×100201411211051³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 100201411211053, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (100201411211053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50100705605525 + 50100705605526.

It is an arithmetic number, because the mean of its divisors is an integer number (50100705605526).

Almost surely, 2^{100201411211051} is an apocalyptic number.

100201411211051 is a deficient number, since it is larger than the sum of its proper divisors (1).

100201411211051 is an equidigital number, since it uses as much as digits as its factorization.

100201411211051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 80, while the sum is 20.

Adding to 100201411211051 its reverse (150112114102001), we get a palindrome (250313525313052).

The spelling of 100201411211051 in words is "one hundred trillion, two hundred one billion, four hundred eleven million, two hundred eleven thousand, fifty-one".