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1002021103117 is a prime number
BaseRepresentation
bin11101001010011010001…
…11001010011000001101
310112210101120111002202001
432211031013022120031
5112404114400244432
62044153325432301
7132252005562646
oct16451507123015
93483346432661
101002021103117
11356a55876651
12142246a0b691
137364ac21448
14366d8a366cd
151b0e8de69e7
hexe94d1ca60d

1002021103117 has 2 divisors, whose sum is σ = 1002021103118. Its totient is φ = 1002021103116.

The previous prime is 1002021103103. The next prime is 1002021103129. The reversal of 1002021103117 is 7113011202001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 781749515556 + 220271587561 = 884166^2 + 469331^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1002021103117 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1002021103094 and 1002021103103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1002021103147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 501010551558 + 501010551559.

It is an arithmetic number, because the mean of its divisors is an integer number (501010551559).

Almost surely, 21002021103117 is an apocalyptic number.

It is an amenable number.

1002021103117 is a deficient number, since it is larger than the sum of its proper divisors (1).

1002021103117 is an equidigital number, since it uses as much as digits as its factorization.

1002021103117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 84, while the sum is 19.

Adding to 1002021103117 its reverse (7113011202001), we get a palindrome (8115032305118).

The spelling of 1002021103117 in words is "one trillion, two billion, twenty-one million, one hundred three thousand, one hundred seventeen".