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100202220031 is a prime number
BaseRepresentation
bin101110101010010000…
…1001000100111111111
3100120122021011011222111
41131110201020213333
53120203232020111
6114010545154451
710145050550164
oct1352441104777
9316567134874
10100202220031
113954a5a4aa1
121750562ba27
1395ab693374
144bc7c6006b
152916d81a21
hex17548489ff

100202220031 has 2 divisors, whose sum is σ = 100202220032. Its totient is φ = 100202220030.

The previous prime is 100202219977. The next prime is 100202220037. The reversal of 100202220031 is 130022202001.

It is a strong prime.

It is an emirp because it is prime and its reverse (130022202001) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-100202220031 is a prime.

It is a super-2 number, since 2×1002022200312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 100202219993 and 100202220020.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100202220037) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50101110015 + 50101110016.

It is an arithmetic number, because the mean of its divisors is an integer number (50101110016).

Almost surely, 2100202220031 is an apocalyptic number.

100202220031 is a deficient number, since it is larger than the sum of its proper divisors (1).

100202220031 is an equidigital number, since it uses as much as digits as its factorization.

100202220031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 13.

Adding to 100202220031 its reverse (130022202001), we get a palindrome (230224422032).

The spelling of 100202220031 in words is "one hundred billion, two hundred two million, two hundred twenty thousand, thirty-one".