10020231113131 has 2 divisors, whose sum is σ = 10020231113132. Its totient is φ = 10020231113130.

The previous prime is 10020231113129. The next prime is 10020231113197. The reversal of 10020231113131 is 13131113202001.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 10020231113131 - 2¹ = 10020231113129 is a prime.

It is a super-2 number, since 2×10020231113131² (a number of 27 digits) contains 22 as substring.

Together with 10020231113129, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 10020231113099 and 10020231113108.

It is not a weakly prime, because it can be changed into another prime (10020231113111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5010115556565 + 5010115556566.

It is an arithmetic number, because the mean of its divisors is an integer number (5010115556566).

Almost surely, 2^{10020231113131} is an apocalyptic number.

10020231113131 is a deficient number, since it is larger than the sum of its proper divisors (1).

10020231113131 is an equidigital number, since it uses as much as digits as its factorization.

10020231113131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 10020231113131 its reverse (13131113202001), we get a palindrome (23151344315132).

The spelling of 10020231113131 in words is "ten trillion, twenty billion, two hundred thirty-one million, one hundred thirteen thousand, one hundred thirty-one".