100204334017 has 2 divisors, whose sum is σ = 100204334018. Its totient is φ = 100204334016.

The previous prime is 100204333951. The next prime is 100204334141. The reversal of 100204334017 is 710433402001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 77381886976 + 22822447041 = 278176^2 + 151071^2 .

It is an emirp because it is prime and its reverse (710433402001) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-100204334017 is a prime.

It is a super-3 number, since 3×100204334017³ (a number of 34 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 100204333982 and 100204334000.

It is not a weakly prime, because it can be changed into another prime (100204334617) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50102167008 + 50102167009.

It is an arithmetic number, because the mean of its divisors is an integer number (50102167009).

Almost surely, 2^100204334017 is an apocalyptic number.

It is an amenable number.

100204334017 is a deficient number, since it is larger than the sum of its proper divisors (1).

100204334017 is an equidigital number, since it uses as much as digits as its factorization.

100204334017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2016, while the sum is 25.

Adding to 100204334017 its reverse (710433402001), we get a palindrome (810637736018).

The spelling of 100204334017 in words is "one hundred billion, two hundred four million, three hundred thirty-four thousand, seventeen".